16^-2b=(1/2)

Solution for 16^-2b=(1/2) equation:

16^-2b=(1/2)

We move all terms to the left:

16^-2b-((1/2))=0

We add all the numbers together, and all the variables

-2b+16^-((+1/2))=0

We add all the numbers together, and all the variables

-2b-((+1/2))=0

We multiply all the terms by the denominator


-2b*2))-((+1=0

Wy multiply elements

-4b^2+1=0

a = -4; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-4)·1
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-4}=\frac{-4}{-8}
=1/2
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-4}=\frac{4}{-8}
=-1/2
$